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Q.

a→,b→ and c→ are unit vectors such that |a→+b→+3c→|=4  Angle between a→ and b→ is θ1 between  b→ and c→ is θ2  a→ and c→ varies [π/6,2π/3] .Then the maximum value of cos⁡θ1+3cos⁡θ2 is

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a

3

b

4

c

22

d

6

answer is B.

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Detailed Solution

|a→+b→+3c→|2=16⇒ |a→|2+|b→|2+9|c→|2+2cos⁡θ1+6cos⁡θ2+6cos⁡θ3=16,θ3∈[π/6,2π/3]  or  2cos⁡θ1+6cos⁡θ2=5−6cos⁡θ3 or  cos⁡θ1+3cos⁡θ2max=4
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