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a,b,c,dR+ such that a, b and c are in A.P. and b, c and d are in H.P., then

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a
ab=cd
b
ac=bd
c
bc=ad
d
none of these

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detailed solution

Correct option is C

2b=a+c,c=2bdb+d⇒2bd=c(b+d)⇒(a+c)d=c(b+d) [as 2b=a+c]⇒ad+cd=bc+cd ⇒bc=ad


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