a,b,c,d∈R+ such that a, b and c are in A.P. and b, c and d are in H.P., then
ab=cd
ac=bd
bc=ad
none of these
2b=a+c,c=2bdb+d⇒2bd=c(b+d)⇒(a+c)d=c(b+d) [as 2b=a+c]⇒ad+cd=bc+cd ⇒bc=ad