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$a, b, c, d \in R such that a, b and c are in A.P and b, c and d are in H.P then$

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ab=cd

ac=bd

bc=ad

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Correct option is C

2b=a+c,c=2bdb+d⇒2bd=c(b+d)⇒(a+c)d=c(b+d)[ as 2b=a+c]⇒ad+cd=bc+cd⇒bc=ad

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a,b,c,d∈R such that a, b and c are in A.P and b,c and d are in H.P then

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$a, b, c, d \in R such that a, b and c are in A.P and b, c and d are in H.P then$