ABC is triangular park with AB=AC=100 m . A clock tower is  situated at the mid-point of BC . The  angles of elevation of the top of  the tower at A and B are cot-13.2 and cosec-12.6 respectively. The  height of the tower is

DP is a clock tower standing at the middle point D of BC . ∠PAD=α=cot−13.2⇒cotα=3.2 and ∠PBD=β=cosec−12.6⇒cosecβ=2.4∴cotβ=cosec2β−1=(5.76)=2.4 In the triangles PAD and PBD , AD=hcotα=3.2h and BD=hcotβ=2.4h In the right angled △ABD,AB2=AD2+BD2⇒1002=(3.2)2+(2.4)2h2=16h2⇒h=25 m.