A and B seek admission in I.I.T. The probability that A is selected is 0.5 and the probability that both A and B are selected is atmost 0.3. The probability of B getting selected is atmost is

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0.5

0.6

0.7

0.8

answer is D.

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Detailed Solution

P(A)=0.5 P(A∩B)≤0.3 now P(A∪B)≤1 ⇒P(A)+P(B)−P(A∩B)≤1 ⇒P(B)≤0.8

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