$\mathrm{A}=\left\{1, 2, 3\right\} \mathrm{and} \mathrm{B}=\left\{3, 8\right\},$ then $\left(\mathrm{A}\cup \mathrm{B}\right)\times \left(\mathrm{A}\cap \mathrm{B}\right)$ is

• A

  $\left\{\left(3, 1\right), \left(3, 2\right), \left(3, 3\right), \left(3, 8\right)\right\}$

• B

  $\left\{\left(1, 3\right), \left(2, 3\right), \left(3, 3\right), \left(8, 3\right)\right\}$

• C

  $\left\{\left(1, 2\right), \left(2, 2\right), \left(3, 3\right), \left(8, 8\right)\right\}$

• D

  $\left\{\left(8, 3\right), \left(8, 2\right), \left(8, 1\right), \left(8, 8\right)\right\}$