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A and B toss a fair coin each simultaneously 50 times. The probability that both of them will not get tail at the same toss is
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a
(3/4)50
b
(2/7)50
c
(1/8)50
d
(7/8)50
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Correct option is A
For each toss, there are four choices:(i) A gets head, B gets head(ii) A gets tail, B gets head(iii) A gets head, B gets rail(iv) A gets tail, B gets tailThus, exhaustive number of ways is 450. Out of the four choices listed above, (iv) is not favorable to the required event in a toss. Therefore, favorable number of cases is 350. Hence, the required probability is ((3/4)50.Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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