A and B toss a fair coin each simultaneously 50 times. The probability that both of them will not get tail at the same toss is

For each toss, there are four choices:(i) A gets head, B gets head(ii) A gets tail, B gets head(iii) A gets head, B gets tail(iv) A gets tail, B gets tailThus, exhaustive number of ways is 450. Out of the four choices listed above, (iv) is not favorable to the required event in a toss. Therefore, favorable number of cases is 350. Hence, the required probability is (3/4)50.