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Q.

A bag contains 20 coins. If the probability that bag contains exactly 4 biased coin is 1/3 and that of exactly 5 biased coin is 2/3, then the probability that all the biased coin are sorted out from the bag in exactly 10 draws is

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a

533 16C6 20C9+111 15C5 20C9

b

233 16C6+515C5 20C9

c

533 16C7 20C9+111 15C6 20C9

d

none of these

answer is C.

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Detailed Solution

P(4 biased coins)=13P(5 biased coins)=14The required probability is13 4C316C6 20C91 11C1+23 5C415C5 20C91 11C1=233 16C6+515C5 20C9
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