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Q.

A bag contains m white and n black balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each pair consists of one white and one black ball is

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a

1/2nCn

b

2n/2nCn

c

2n/n!

d

2n/(2n!)

answer is B.

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Detailed Solution

The required probability is        n2 2nC2(n−1)22n−2C2(n−2)2 2n−4C2⋯22 4C212 2C2=(1×2×3×4×⋯×(n−1)n)2(2n)!2n=2n(n!)2(2n)!=2n 2nCn
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