In a bag there are 5 half rupee coins, 4 twenty paise coins and 4 ten paise coins. If two coins are drawn from the bag at random then the probability that the amount drawn to be minimum is
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a
913
b
413
c
213
d
113
answer is D.
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Detailed Solution
n(S) = 13C2 = 13×6 Sum is minimum if both coins are ten paise coins.So n(E) = 4C2 = 6 The probability that the amount drawn to be minimum is P(E) = 613×6 = 113