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Q.

The base of the pyramid AOBC is an equilateral triangle OBC with each side is equal to 42. ‘O’ being the origin of reference, AO is perpendicular to the plane of triangle OBC and AO = 2. Then the cosine of the angle between the skew lines one passes through A and midpoint of OB, and the other passing through O and the mid point of BC can be

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a

−12

b

0

c

16

d

12

answer is A.

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Detailed Solution

Take OB as X-axis. we have B=(42,0,0),A=(0,0,2) and C=(22,26,0). Mid point of OB is (22,0,0), Mid point of BC is (32,6,0), hence the direction ratios of the lines be 22:0:−2 and 32:10:0
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