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The base of the pyramid AOBC is an equilateral triangle OBC with each side is equal to $4\sqrt{2}$. ‘O’ being the origin of reference, AO is perpendicular to the plane of triangle OBC and AO = 2. Then the cosine of the angle between the skew lines one passes through A and midpoint of OB, and the other passing through O and the mid point of BC can be

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a

−12

b

0

c

16

d

12

detailed solution

Correct option is A

Take OB as X-axis. we have B=(42,0,0),A=(0,0,2) and C=(22,26,0). Mid point of OB is (22,0,0), Mid point of BC is (32,6,0), hence the direction ratios of the lines be 22:0:−2 and 32:10:0

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