In a battle 70 % of the combatants lost one eye, 80 % an ear, 75 % an arm, 85 % a leg, n% lost all the four limbs. The minimum value of n is

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answer is 10.

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Detailed Solution

Let A be the event of getting a person who loss one eye, P(A)=0.7 Let B be the event of getting a person who loss an ear, P(B)=0.8 Let C be the event of getting a person who loss an arm, P(C)=0.75 Let D be the event of getting a person who loss a leg, P(D)=0.85 Suppose that the probability of gettting a person who lost all the four limbs is xPA∩B∩C∩D=1−PA∩B∩C∩D¯=1−PA¯∪B¯∪C¯∪D¯>1−PA¯+PB¯+PC¯+PD¯=1−1−0.7−1−0.8−1−0.75−1−0.85=1−0.3−0.2−0.25−0.15=0.1Therefore, the value of n is 10%

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