A beam of light is sent along the line x−y=1, which after refracting from the x-axis enters the opposite side by turning through 300 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is

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2−3x−y=2+3

2+3x−y=2+3

2−3x+y=(2+3)

y=2−3x−1

answer is D.

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Detailed Solution

From the figure, the refracted ray make an angle of 150 with the positive direction of the x-axis and passes through the point 1,0. Its equation is y−0=tan150x−1or y=2−3x−1

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