Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A beam of light is sent along the line x−y=1, which after refracting from the x-axis enters the opposite side by turning through 300 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2−3x−y=2+3

b

2+3x−y=2+3

c

2−3x+y=(2+3)

d

y=2−3x−1

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

From the figure, the refracted ray make an angle of 150 with the positive direction of the x-axis and passes through the point 1,0. Its equation is y−0=tan150x−1or y=2−3x−1
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon