A beam of light is sent along the line x−y=1, which after refracting from the x-axis enters the opposite side by turning through 300 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2−3x−y=2+3
b
2+3x−y=2+3
c
2−3x+y=(2+3)
d
y=2−3x−1
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
From the figure, the refracted ray make an angle of 150 with the positive direction of the x-axis and passes through the point 1,0. Its equation is y−0=tan150x−1or y=2−3x−1