Q.
A beam of light is sent along the line x−y=1, which after refracting from the x-axis enters the opposite side by turning through 300 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is
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a
2−3x−y=2+3
b
2+3x−y=2+3
c
2−3x+y=(2+3)
d
y=2−3x−1
answer is D.
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Detailed Solution
From the figure, the refracted ray make an angle of 150 with the positive direction of the x-axis and passes through the point 1,0. Its equation is y−0=tan150x−1or y=2−3x−1
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