Between 1 and 31 are inserted M arithmetic means so that the ratio of the 7th and (M - 1) th means is 5:9, then the value of m is
13
14
11
12
let A1, A2,.,. , Am be ,m arithmetic means between 1 and 31.
⇒Then A1,A2,…,Am31 is an AP with common difference.
d=31−1m+1=30m+1 ∵d=b−an+1
∴ A7=1+7d
=1+7×30m+1=m+211m+1
and Am−1=1+(m−1)d=1+30m+1(m−1)=31m−29m+1
Now, A7Am−1=59m+21131m−29=59⇒ 9m+1899=155m−145⇒ 146m=2044⇒ m=14 (given)