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Between two numbers whose sum is 216, an even  number of arithmetic means are inserted. If the sum of these means exceeds their number by unity, then the number of means are

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a
12
b
10
c
8
d
None of these

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detailed solution

Correct option is A

Let 2n arithmetic means be A1, A2, A3, …, A2n between a and b.  Then A1+A2+A3+…+A2n=a+b2×2n=1362×2n=13n6Given, A1+A2+A3+…+A2n=2n+1∴    2n+1=13n6; or 12n+6=13n∴    n=6∴ The number of means =2n=2×6=12.


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Between 1 and  31  are  inserted  M arithmetic means so that the ratio of the 7th  and  (M - 1) th  means is 5:9,  then the  value  of m is 


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