The bi quadratic equation, two of whose roots are 1+i, 1−2 is

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x4−4x3+5x2−2x−2=0

x4−4x3−5x2+2x+2=0

x4+4x3−5x2+2x−2=0

x4+4x3+5x2−2x+2=0

answer is A.

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Detailed Solution

1±i,1±2 are the roots of the given equation hence the required equation is =x-1+ix-1-ix-1+2x-1-2=0⇒x2-2x+2x2-2x-1=0⇒x4−4x3+5x2−2x−2=0

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