Q.

The binomial expansion of (1+x)n is

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a

C0+C1+C2+C3+.......Cn

b

C0−C1+C2−C3+.......+(−1)nCn

c

C0+C1x+C2x2+.......+Cnxn

d

C0−C1x+C2x2+.......+(−1)nCnxn

answer is C.

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Detailed Solution

(a+b)n=nc0anb0+nC1an-1b1+nc2an-2b2+……..+nCna0bn   Put a=1;b=x;(1+x)n=nc01nx0+nC11n-1x1+nc21n-2x2+……..+nCn10xn=nc0+nC1x+nc2x2+……..+nCnxn=C0+C1x+C2x2+……..+Cnxn
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The binomial expansion of (1+x)n is