The bisectors BD and CF of a triangle ABC have equations y = x and x = 10. If A is (3, 5), then the equation of BC is

Clearly, reflection of A (3,5) on y = x is (5,3) and reflection of  A(3,5)  with respect to x =10 be (x2,5) midpoint of A(3,5) and (x2,5) =(10,5) on x=10 ∴ the other point is (17,5)So (5,3) and (17,5) should lie on BC. Therefore, equation of BC is⇒ y−3=5−317−5(x−5)⇒ 6y−x=13