Questions
The bisectors BD and CF of a triangle ABC have equations y = x and x = 10. If A is (3, 5), then the equation of BC is
a
5y−2x=11
b
6y−5x=17
c
6y−x=13
d
None of these
detailed solution
Correct option is C
Clearly, reflection of A (3,5) on y = x is (5,3) and reflection of A(3,5) with respect to x =10 be (x2,5) midpoint of A(3,5) and (x2,5) =(10,5) on x=10 ∴ the other point is (17,5)So (5,3) and (17,5) should lie on BC. Therefore, equation of BC is⇒ y−3=5−317−5(x−5)⇒ 6y−x=13Talk to our academic expert!
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