A box contains $$10$$ mangoes out of which $$4$$ are rotten. Two mangoes are taken out together. If one of them is found to be good, then the probability that the other is also good, is

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Infinity Learn · Accepted Answer

Let A be the event that the first mango is good. Then required probability is $$PBA=P(A$$∩$$B)P(A)$$ Probability that both mangoes are good is $$p(A$$∩$$B)=$$ $$6C2$$ $$10C2$$ Probability that first mango is good is PA $$=C6$$,$$2C10$$,$$2+C6$$,$$1$$·$$C4$$,$$1C10$$,$$2PBA=PA$$∩$$BPA=C6$$,$$2C6$$,$$2+C(6$$,$$1)$$·$$C4$$,$$1=1539=513$$

A box contains 10 mangoes out of which 4 are rotten. Two mangoes are taken out together. If one of them is found to be good, then the probability that the other is also good, is

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