Questions
A box contains 10 mangoes out of which 4 are rotten. Two mangoes are taken out together. If one of them is found to be good, then the probability that the other is also good, is
detailed solution
Correct option is B
Let A be the event that the first mango is good. Then required probability is PBA=P(A∩B)P(A) Probability that both mangoes are good is p(A∩B)= 6C2 10C2 Probability that first mango is good is PA =C6,2C10,2+C6,1·C4,1C10,2PBA=PA∩BPA=C6,2C6,2+C(6,1)·C4,1=1539=513Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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