A box contains $$100$$ tickets, numbered $$1$$, $$2$$, ...$$.100$$. Two tickets are chosen at random one after another with replacement. It is given that the maximum sum on the two chosen tickets is not more than $$10$$. The minimum sum of them is $$5$$ with probability

Question

A box  contains $$100$$ tickets, numbered $$1$$, $$2$$, ...$$.100$$. Two tickets are chosen at  random one after another with replacement. It is given that the maximum sum  on the two chosen tickets is not more than $$10$$. The minimum sum of them is $$5$$  with probability

Infinity Learn · Accepted Answer

For getting  $$sum-2possi$$→$$1$$                                     $$3possi$$→$$2$$                                    .                               .                               .                                          $$10possi$$→$$9$$     $$P(E1)=45$$     $$P(E1$$∩$$E2)=39$$     $$P(E2E1)=3945=1315$$

A box contains 100 tickets, numbered 1, 2, ....100. Two tickets are chosen at random one after another with replacement. It is given that the maximum sum on the two chosen tickets is not more than 10. The minimum sum of them is 5 with probability

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