First slide

Introduction to statistics

Question

A box contains 6 tickets. Two of the tickets carry a price of Rs. 5/- each, the other 4 carry a price of Rs.1/-. If one ticket is drawn, the mean value of the price is

NA

A

$\frac{14}{3}$
B

$\frac{7}{6}$
C

1
D

$\frac{7}{3}$

Solution

$T h e w e i g h t e d m e a n = \frac{2 (5) + 4 (1)}{6} = \frac{14}{6} = \frac{7}{3}$

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