Questions
By eliminating from the homogenous equations where not all zero
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a
xy+yz+zx=1
b
xy+yz+zx=−1
c
x+y+z=0
d
x+y+z=1
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Correct option is B
x=ab−c⇒a=xb−xc⇒a−xb+xc=0→(1)y=bc−a⇒b=yc−ya⇒ya+b−yc=0→(2)z=ca−b⇒c=za−zb⇒za−zb−c=0→(3) By eliminating a.b,c from (1), (2), (3), we get 1−xxy1−yz−z−1=0⇒1(−1−yz)+x(−y+yz)+x(−yz−z)=0⇒−1−yz−xy+xyz−xyz−zx=0⇒xy+yz+zx=−1Similar Questions
If the system of equations,
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