By elimination of a,b,cfrom the homogeneous equations x=ab−c, y=bc−a, z=ca−bwhere a,b,cnot all zero.
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a
xy+yz+zx=1
b
xy+yz+zx=−1
c
x+y+z=0
d
x+y+z=1
answer is B.
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Detailed Solution
a−xb+xc=0→(1) ya+b−yc=0→(2)za−zb−c=0→(3)Since a, b, c are not all zero, the above system has a non-trivial solution.By eliminating a,b,cfrom (1),(2),(3),we get1-xxy1-yz-z-1=0 ⇒xy+yz+zx=−1