Q.
By principle of mathematical induction cosθcos2θcos4θ…cos2n−1θ,∀n∈N=
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
sin2nθ2nsinθ
b
cos2nθ2nsinθ
c
sin2nθ2n−1sinθ
d
None of these
answer is A.
(Unlock A.I Detailed Solution for FREE)
Detailed Solution
Let P(n):cosθcos2θcos4θ…cos2n−1θ=sin2nθ2nsinθ… (i) Step l :For n=1, LHS=cosθ and RHS =sin2θ2sinθ=cosθ P(1 ) is true. Step ll :Let P(n) is true, thenP(k):cosθcos2θcos4θ…cos2k−1θ=sin2kθ2ksinθStep III: For n=k+1P(k+1):cosθcos2θ…cos2kθ=sin2k+1θ2k+1sinθ LHS =cosθcos2θ…cos2(k−1)θcos2kθ=sin2kθ2ksinθ⋅cos2kθ=2sin2kθ⋅cos2kθ2k+1sinθ=sin2k+1θ2k+1sinθ=RHS For n =k + 1, P(n) is true. Hence, by principle for mathematical induction for all n ∈ N,P(n) is true.
Watch 3-min video & get full concept clarity