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$C_{0} + 4 \cdot C_{1} + 7 . C_{2} + . (n + 1) terms =$

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detailed solution

Correct option is A

(n+1) th term of 1,4,7,… is 1+n(3)=3n+1 . Sum =(3n+1+1)2n−1=(3n+2)2n−1

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C0+4⋅C1+7.C2+.(n+1) terms =

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$C_{0} + 4 \cdot C_{1} + 7 . C_{2} + . (n + 1) terms =$