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Q.

C0+C1x2+C2x23+...........+Cnxnn+1=

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a

1(n+1)x

b

(1+x)n(n+1)x

c

(1+x)(n+1)(n+1)x

d

(1+x)(n+1)−1(n+1)x

answer is D.

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Detailed Solution

S=1+n2!x+n(n−1)3!x2+…+xnn+1x⋅S=x+1+n2!x2+n(n−1)3!x3+…+xn+1n+1(n+1)x(S)=(n+1)x+(n+1)n2!x2+(n+1)n(n−1)3!x3+…+(n+1)xn+1n+11nn+1C1x+n+1C2x2+…n+1Cn+1xn+1−1=(1+x)n+1−1S=(1+x)n+1−1x(n+1)
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