First slide

Introduction to ITF

Question

$C o s^{- 1} (C o s 10) =$

Moderate

A

10
B

$4 π - 10$
C

$10 - 4 π$
D

$4 π + 10$

Solution

Here $θ = 10$ radians. clearly, it does not lies between 0 and $π$ . But $4 π - 10$ lies between $0$ and $π$ .
$∴$ $C o s^{- 1} (C o s 10) = C o s^{- 1} (C o s (4 π - 10))$
$= 4 π - 10$

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