CosSin−$$1(2cos2$$θ−$$1)+Cos$$−$$1(1$$−$$2sin2$$θ$$)=$$

Question

Infinity Learn · Accepted Answer

We know that $$2cos2$$θ−$$1=1$$−$$2sin2$$θ$$=cos2$$θ ∴$$cossin-1$$ $$2cos2$$θ−$$1+$$$$cos$$$$-11$$−$$2sin2$$θ$$=cossin-1$$ $$cos2$$θ$$+$$$$cos$$$$-1cos2$$θ                                                                                  $$=cossin-1$$ $$sin$$$$π$$$$2-2$$θ$$+$$$$cos$$$$-1cos2$$θ                                                                                  $$=$$$$cos$$$$π$$$$2-2$$θ$$+2$$θ                                                                                   $$=0$$

$C o s [S i n^{- 1} (2 \cos^{2} θ - 1) + C o s^{- 1} (1 - 2 \sin^{2} θ)] =$

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CosSin−1(2cos2θ−1)+Cos−1(1−2sin2θ)=

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$C o s [S i n^{- 1} (2 \cos^{2} θ - 1) + C o s^{- 1} (1 - 2 \sin^{2} θ)] =$