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Cards are drawn one by one without replacement from a pack of 52 cards. The probability that 10 cards will precede the first ace is
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a
2141456
b
1644165
c
451884
d
None of these
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Correct option is D
Let event Abe drawing cards which are not ace and B be drawing an ace card. Therefore, the required probability isP(A∩B)=P(A)×P(B)Now, there are four aces and 48 other cards. Hence,P(A)= 48C9 52C9After having drawn 10 non-ace cards, the l1th card must be ace.Hence,P(B)= 4C1 42C1=442Hence,P(A∩B)= 48C9 52C9442Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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