The cartesian equation of line is x−53=y+47=z−62 its vector form is

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r¯=(5i¯+4j¯+6k¯)+λ(3i¯+2j¯+2k¯)

r¯=(5i¯−4j¯+6k¯)+λ(3i¯+7j¯+2k¯)

r¯=(5i¯+4j¯+6k¯)+λ(3i¯+7j¯+2k¯)

r¯=(−5i¯+4j¯+6k¯)+λ(3i¯+7j¯+2k¯)

answer is B.

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Detailed Solution

x−53−y+47=z−62=λ x=5+3λ,y=-4+7λ,z=6+2λ r↔=xi⇀+yj⇀+zk subtute→

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