The centre of the circle x = 2 + 3 cos θ, y = 3 sin θ- 1, is
(3, 3)
(2,-1)
(-2,1)
(-1, 2)
We have,
x=2+3cosθ and y=3sinθ−1⇒(x−2)2+(y+1)2=32
Clearly, it is the equation of a circle having its centre at (2, -1).