The in centre of the triangle with vertices (1,3),(0,0) and (2,0) is
(1,3/2)
(2/3,1/3)
(2/3,3/2)
(1,1/3)
Let the vertices of the triangle be A(1,3), B (0, 0) and C (2, 0). We observe that
AB=2=BC=AC
So, the triangle is equilateral. Consequently, its incentre coincides with the centroid whose coordinates are.
1+0+23,3+0+03=1,13