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Q.

The centroid of the triangle formed by the pair of straight lines 12x2−20xy+7y2=0 and the line 2x−3y+4=0 is

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a

−73,73

b

−83,83

c

83,83

d

43,43

answer is C.

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Detailed Solution

a=12,2h=−10,b=7,l=2,m=−3,n=4αbl−hm=βam−hl=−2n3(am2−2hlm+bl2)⇒(α,β)=83,83
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