Questions
The chance of one event happening is the square of the chance of a second event, but the odds against the first are cube of the odds against the second. The chance of the first event is
detailed solution
Correct option is B
Let the two events be E1 andE2 . Let their chances be p and q respectively. Then p=q2 …………….(i) The chances of not happening of the events are 1−p and 1−q respectively.Odds against the first event = 1−pp Odds against the second event = 1−qq Given 1−pp =(1−qq)3⇒1−q2q2=(1−q)3q3[from (i)] ⇒(1−qq2)[(1+q)−(1−q)2q]=0 ∵q≠1 and q≠0 ∴q(1+q)=1−2q+q2⇒q=13 ∴ from (i) p=q2=19 ∴p(E1)=p=19Similar Questions
A coin whose faces are marked 3 and 5 is tossed 4 times. The odds against the sum of the numbers thrown being less than 15 are
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