A chord is drawn through the focus of the parabola y2 = 6x such than its distance from the vertex of this parabola is 52 , then its slope can be

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answer is A.

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Detailed Solution

Focus of the parabola is 32,0 Let the equation of the chord be y=mx−32Its distance from the vertex (0, 0) is −3m21+m2=52⇒9m2=51+m2⇒m2=54⇒m=52

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