First slide
Trigonometric Identities
Question

A circle centered at O has radius 1 and contains point ,A Segment AB is tangent to the circle at A and AOB = θ
If point C lies on OA, and BC bisects the angle ABO, then OC equals

Moderate
Solution

Using property of angle bisector, we get 

OBAB=OCACsecθtanθ=x1x or  x=secθsecθ+tanθ =secθ(secθtanθ)=11+sinθ

 

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