Questions
A circle of constant radius a passes through the origin 0 and cuts the axes of coordinates at points P and Q. Then the equation of the locus of the foot of perpendicular from O to PQ is
detailed solution
Correct option is C
The equation of line PQ isy−k=−hk(x−h)or hx+ky=h2+k2∴ Q≡h2+k2h,0 and P≡0,h2+k2kAlso, 2a=x12+y12or x12+y12=4a2Eliminating x1 and y1we havex2+y221x2+1y2=4a2Talk to our academic expert!
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The locus of the point which moves in a plane so that the sum of the squares of its distances from the lines
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