A circle of radius 2 units rolls inside the rim of the circle x2+y2+8x−2y−19=0 then the locus of its centre is
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a
x2+y2+8x+2y−47=0
b
x2+y2+8x−2y−1=0
c
x2+y2+8x−2y+1=0
d
x2+y2−8x+2y+1=0
answer is C.
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Detailed Solution
The locus of the centres form a circle concentric with the given circle centre of the circle is (-4,2) and radius is 6-2locus of the circle with centres is (x+4)2+(y−1)2=(6−2)2 x2+y2+8x−2y+1=0