Q.

A circle of radius 2 units rolls inside the rim of the circle x2+y2+8x−2y−19=0  then the locus of its centre is

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a

x2+y2+8x+2y−47=0

b

x2+y2+8x−2y−1=0

c

x2+y2+8x−2y+1=0

d

x2+y2−8x+2y+1=0

answer is C.

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Detailed Solution

The locus of the centres form a circle concentric with the given circle centre of the circle is (-4,2) and radius is 6-2locus of the circle with centres is  (x+4)2+(y−1)2=(6−2)2 x2+y2+8x−2y+1=0
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A circle of radius 2 units rolls inside the rim of the circle x2+y2+8x−2y−19=0  then the locus of its centre is