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For a circle two diameters are $2 x + y - 1 = 0, x + y + 1 = 0$ then centre is

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(2,3)

(−2,3)

(−2,−3)

(2,−3)

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detailed solution

Correct option is D

Given diameters are 2x+y−1=0 ….(1), x+y+1=0 …..(2)Centre=point of intersection of (1) & (2)=(2,3)(∵⇒x1+1=y−1−2=12−1⇒x=2,y=−3 )

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For a circle two diameters are 2x+y−1=0, x+y+1=0 then centre is

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For a circle two diameters are $2 x + y - 1 = 0, x + y + 1 = 0$ then centre is