The circle with centre (−2,3)  and radius being the distance between the parallel lines 2x−y+5=0, 2x−y+15=0 is

Given lines are 2x−y+5=0 ….(1), 2x−y+15=0 ….(2) and centre(−2,3) r= Distance between the parallel lines 2x−y+5=0,2x−y+15=0 =|c1−c2|a2+b2=|5−15|4+1=105 =25 c=(−2,3), r=25 ∴ The equation of the circle is (x−h)2+(y−k)2=r2 ⇒(x+2)2+(y−3)2=20 ⇒x2+y2+4x−6y−7=0