The circle x2+y2=4 cuts the circle x2+y2−2x−4=0 at the points A and B. If the circle x2+y2−4x−k=0 passes through A and B then the value of k, is

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answer is 4.

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Detailed Solution

The circle x2+y2=4 cuts the circle x2+y2−2x−4=0 at A(0,2) and B(0,−2)The circle x2+y2−4x−k=0 passes through A and B. Therefore0+4−0−k=0⇒k=4

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