The circle x2+y2=4 cuts the circle x2+y2−2x−4=0 at the points A and B. If the circle x2+y2−4x−k=0 passes through A and B then the value of k, is
The circle x2+y2=4 cuts the circle x2+y2−2x−4=0 at A(0,2) and B(0,−2)
The circle x2+y2−4x−k=0 passes through A and B. Therefore
0+4−0−k=0⇒k=4