The circle x2+y2=4 cuts the circle x2+y2+2x+3y−5=0 in A and B. Then the equation of the circle on AB as diameter, is

The equation of the circle on AB as diameter is x2+y2−4+λ(2x+3y−1)=0Using⁡S1+λS2−S1=0 or, x2+y2+2λx+3λy−(λ+4)=0The equation of AB is2x+3y−1=0Ii AB is a diameter of (i), then centre lies on AB.−2λ−9λ2−1=0⇒λ=−21313x2+13y2−4x−6y−50=0