The circle x2+y2=4 cuts the circle x2+y2+2x+3y−5=0 in A and B. Then the equation of the circle on AB as diameter, is
13x2+y2−4x−6y−50=0
9x2+y2+8x−4y+25=0
x2+y2−5x+2y+72=0
none of these
The equation of the circle on AB as diameter is
x2+y2−4+λ(2x+3y−1)=0UsingS1+λS2−S1=0
or, x2+y2+2λx+3λy−(λ+4)=0
The equation of AB is
2x+3y−1=0
Ii AB is a diameter of (i), then centre lies on AB.
−2λ−9λ2−1=0⇒λ=−213
13x2+13y2−4x−6y−50=0