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Circle $x^{2} + y^{2} + 2 x - 8 y - 8 = 0$ and $x^{2} + y^{2} + 2 x - 6 y - 6 = 0$

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touch each other internally at (–1, – 1)

touch each other externally at (−1,−1)

intersect each other at (–1, – 1)

none of these.

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detailed solution

Correct option is A

Centre of the first circle is (–1, 4) and its radius is 1+16+8=5 Centre of the second circle is(−1,3) ) and its radius is 1+9+6=4

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Circle x2+y2+2x−8y−8=0 and x2+y2+2x−6y−6=0

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Circle $x^{2} + y^{2} + 2 x - 8 y - 8 = 0$ and $x^{2} + y^{2} + 2 x - 6 y - 6 = 0$