Q.

Circles are drawn through the point (2,0)  to cut intercept of length ‘5’ units on the x-axis . If their centres lie  in the first quadrant then their equation is

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a

x2+y2−9x+2ky+14=0,k>0

b

3x2+3y2+27x−2ky+42=0,k>0

c

x2+y2−9x−2ky+14=0,k>0

d

x2+y2−2ky−9y+14=0,k>0

answer is C.

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Detailed Solution

(C)      c=(92,k) (x−92)2+(y−k)2=254+k2 (or) x2+y2−9x−2ky+14=0
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