The circles x2+y2−10x+16=0 and x2+y2=r2 intersect each other in two distinct points if
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a
r<2
b
r<8
c
2
d
2≤r≤8
answer is C.
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Detailed Solution
Centres of the given circles are C1(5,0) and C2(0,0) and their radii are r1=3 and r2=r respectively. For the circles to intersect at two distinct points, we must have r1−r22⇒2