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Analysis of two circles in circles

Question

The circles x2+y2+x+y=0 and x2+y2+xy=0 intersect at an angle of 

Moderate
Solution

The angle 8 of intersection of two cirlces is given by 

cosθ=r12+r22C1C222r1r2

where r1 , r2 are radii of two circles and C1 C2 is the distance between their centres. 

Here, r1=14+14=12=r2 and C1C2=1

 cosθ=0θ=π2

ALITER For the two circles, we find that 2g1g2+f1f2=c1+c2

hold. So, the angle of intersection is a right angle. 



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