The circum centre of triangle formed by (acosα,asinα),(acosα,asinα),(acosα,asinα) is

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(0,0)

(1,1)

(1,−1)

(0, 1)

answer is A.

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Detailed Solution

Clearly the points are equidistance from (0,0) ⇒ the equidistance is the radius hence circumcentre is (0,0)

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