The circumcentre of triangle formed by the points1,2,3,3,−1,5,4,0,−3is

Let the vertices are A1,2,3,B3,−1,5,C4,0,−3The sides are      AB=4+9+4=17BC=1+1+64=66CA=9+4+36=49       Observing the sides of the triangle, square of one side is sum of squares of other two sides, so that the triangle is right angled triangle. Hence, the circum center is midpoint of hypotenuse. It is midpoint ofBCTherefore, the circum center is  3+42,−1+02,5−32=72,−12,1