Questions
The circumcentre of triangle formed by the pointsis
detailed solution
Correct option is A
Let the vertices are A1,2,3,B3,−1,5,C4,0,−3The sides are AB=4+9+4=17BC=1+1+64=66CA=9+4+36=49 Observing the sides of the triangle, square of one side is sum of squares of other two sides, so that the triangle is right angled triangle. Hence, the circum center is midpoint of hypotenuse. It is midpoint ofBCTherefore, the circum center is 3+42,−1+02,5−32=72,−12,1Talk to our academic expert!
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