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Q.

The circumcentre of a triangle with vertices  A (5, 3),  B(1,5), C(0, 7)

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a

(1, 0)

b

(3, 5)

c

(0, 1)

d

(11, 20)

answer is D.

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Detailed Solution

⊥le  bisector of AB¯  2 x – y = 2 ⊥le  bisector of AC¯  5 x – 2y = 15∴  circumecentre  (11, 20)
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